Puzzles
271. In a class there are less than 500 students . when it is divided by 3 it gives a whole number. similarly when it is divided by 4,5 or 7 gives a whole number.find the no. of students in the class.ans: 420
272. Uncle reuben and aunt cynthia came to town to shop reuben bought a suit and hat for $15
cynthia paid as much as for her hat as reuben did for his suit then she spent the rest of their
money for a new dress on the way home cynthia called reuben's attention to the fact that his hat
cost $1 more than her dress then she added if we had divided our hat money differently so that
we bought different hats mine costing 1 and 1/2 time cost if yours then we each would have spent
the same amount of money in that case said uncle reuben "how much would my hat have cost"
Ans : Uncles hat costs $6.4 (total money was $29)
273. Four family names are given and their frends name are given but not in order.( u hav to find
which frend belongs to which family) Each frend prepares salad using 3 different fruits . they are
given apple, cherry, grape, banana., no two frens uses the same combination.
Various conditions are given and 4 ques asked.
Which fruit did mandy didn't use?
Who is flures friend?
Name the fruits common btwn Erica and stacy?
274.Here is a simple mathematical puzzle set by Longfellow in his own flowery, poetical language.
If 1/5th of a hive of bees flew to the badamba flower, 1/3rd flew to the slandbara, 3 times the
difference of these two numbers flew to an arbour, ad one bee continued to fly about, attracted on each side by the fragrant ketaki and malati, what was the total number of bees?
Ans: 15
275. (don't remember the exact question)a man while sorting files picks up file number one,misses
one, picks up file no. 2,mises two files,and so on...after that he found that he picked up 5% of the
files. How many files were there?
Ans:39
276. A man walks at 4 km/hr on plain, then at 3 km/hr uphill and then returns through the same road at 6 km/hr downhill and at 4 km/hr on the plain. It takes altogether 6 hours. So what distance he covered in one way?
Ans: 12 km
Solution: Let plain road = x km
And hill road = y km
? x/4 + y/3 + y/6 + x/4 = 6
? x/2 + y/2 = 6
? x + y =12
277. There are some men and some lodges for which the
following conditions hold true –
i) Each lodge is represented by exactly 3 men .
ii) Each man is associated with exactly 2 lodges.
iii) Any pair of lodge has only one man in common.
How many men and how many lodges were there?
Ans: 6 men and 4 lodges.
Solution:
i) L1 is represented by M1, M2, M3. L2 is represented by M3, M4, M5. L3 is represented by M1, M4, M6. L4 is represented by M2, M5, M6.
ii) M1 is associated with L1,L3. M2 is associated with L1,L4. M3 is associated with L1,L2. M4 is associated with L2,L3. M5 is associated with L2,L4. M6 is associated with L3,L4.
iii) Common between L1 and L2 is only M3. Common between L1 and L3 is only M1. Common between L1 and L4 is only M2. Common between L2 and L3 is only M4. Common between L2 and L4 is only M5. Common between L3 and L4 is only M6.
i.e all the given conditions are satisfied.
278. A person sells 2 items for Rs. 12 each. For one he
profits 25% and for the other he losses 20%. Altogether did he loss or gain? And by how much?
Ans: He losses by 60 paise.
Solution: Cost price of the item for which he losses = Rs.
12*100/80 = Rs. 15.
Cost price of the item for which he Gains = Rs.
12*100/125 = Rs 9.6.
? Total cost price is Rs. 24.6 and total sell price is
Rs. 24.
So altogether he losses by Rs. 0.6.
279. My father’s age was x in the year x². I am obviously talking about 20th century. In which year was my father born?
Ans: In the year 1892.
Solution: x = 44 as 44² = 1936 and the square of any other
integer will not fall in between 1900 and 2000. i.e my
father was 44 in the year 1936. ? my father was
born in the year 1892.
280.A man was going by cycle. After going 2/3rd of total distance the cycle broke down and he had to complete the journey on foot. At the end he found that he walked twice as long as he was on cycle. How many times the speed of the cycle is as the speed of walking?
Ans: 4 times.
Solution: Let the distance be z km, speed of cycle be x km/hr
and walking speed be y km/hr.
Then he covered 2z/3 km by cycle in 2z/3x hr and
covered z/3 km on foot in z/3y hr.
? according to the question 2*2z/3x = z/3y ? x/y = 4.